Voltmeter


A voltmeter is a tool used to measure electric potential differences within a circuit. It is attached in parallel at the ends of an electrical resistance (or some other combination of components) whose potential drop needs to be measured and is specifically designed to have an extremely high internal resistance to avoid causing a significant split in the current passing through the node where the voltmeter is attached.

Mechanism

A voltmeter is actually built from an ammeter. A voltmeter is essentially just an ammeter in series with a really large1 additional resistance RaddR_\text{add}. In such a circuit, we have

Rvolt=Ramm+RaddR_\text{volt}=R_\text{amm}+R_\text{add}

here RammR_\text{amm} is the resistance of the ammeter (probably tiny). The voltmeter is applied in parallel to the actual resistance RR we are trying to measure the drop of, so there are two branches. In parallel circuits, the potential is identical in both branches, but the current is split, as per Kirchhoff's laws. Call II the total current and IvoltI_\text{volt} the one going through the voltmeter branch. Then

ΔV=(IIvolt)R,ΔVvolt=IvoltRvolt(1)\Delta V=(I-I_\text{volt})R,\qquad \Delta V_\text{volt}=I_\text{volt}R_\text{volt}\tag{1}

but as we said, the potential is the same across branches, so ΔV=ΔVvolt\Delta V=\Delta V_\text{volt} when taking the measurement. However, this is a key detail. These two are the same only when the voltmeter is attached to measure, but because attaching the voltmeter splits the current, the measured ΔV\Delta V will not be the true ΔV\Delta V, as the voltmeter "steals" some current from the main circuit, thus reducing the potential drop. Therefore, the voltmeter's measured potential is guaranteed to be an underestimate of the real potential drop that occurs when the voltmeter is not present.

This difference can be quantified. The true potential drop is given by

ΔVtrue=IR\Delta V_\text{true}=IR

which differs from the measured one

ΔVmeas=(IIvolt)R\Delta V_\text{meas}=(I-I_\text{volt})R

due to the voltmeter taking away some of the current. They are equal only when

ΔVtrue=IR=(IIvolt+Ivolt)R=(ΔVmeasR+ΔVmeasRvolt)R\Delta V_\text{true}=IR=(I-I_\text{volt}+I_\text{volt})R=\left( \frac{\Delta V_\text{meas}}{R}+ \frac{\Delta V_\text{meas}}{R_\text{volt}} \right)R

by using (1)(1), so

ΔVtrue=ΔVmeas(1+RRvolt)\boxed{\Delta V_\text{true}=\Delta V_\text{meas}\left( 1+ \frac{R}{R_\text{volt}} \right)}

RvoltR_\text{volt} is chosen during manufacturing, so as long as RR is known, ΔVmeas\Delta V_\text{meas} is the only necessary measurement to recover the real voltage drop. In turn, this means measuring IvoltI_\text{volt} as per usual with the ammeter. Note how when R/Rvolt0R/R_\text{volt}\to 0, ΔVtrue=ΔVmeas\Delta V_\text{true}=\Delta V_\text{meas}. Thus, we want our voltmeter resistance to be as high as possible compared to the circuit we're measuring.

Footnotes

  1. By large we mean with respect to the resistance causing the voltage drop we are measuring.